Q 1374823756.     When a hydrogen atom emits a photon of energy `12.1` eV, the orbital angular momentum changes by

A

`1.05 times10^{-34}` Joule.sec

B

`2.11 times10^{-34}` Joule.sec

C

`3.16 times10^{-34}` Joule.sec

D

`4.22 times10^{-34}` Joule.sec

HINT

Use formula: Change in angular momentum `=(n_2 - n_1) frac{h}{2 pi}`
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