Q .     Reduction potential for the following half-cell reactions are

`Zn = Zn^(2+) +2e^- ; E^0 = +0.76 V`

`Fe = Fe^(2+) +2e^- ; E^0 = +0.44 V`

The EMF for the cell reaction `Fe^(2+) +Zn → Zn^(2+) +Fe ` will be

AIPMT 1996
A

`-0.32 V`

B

`+1.20 V`

C

`-1.20 V`

D

`+0.32 V`

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