Q 1331791622.     If `text()^5nC_{r-1}=36text()^5,nC_r=84` and `text()^5nC_{r+1}=126` then find `text()^5rC_2`

A

`1`

B

`2`

C

`4`

D

`3`

HINT

Use `{text()^nC_r}/{text()^nC_{r-1}}= {n-r+1}/{r}`

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