Q 1606678578.     Let `f` be an odd function defined on the set of real numbers such that for `x\ge 0, f(x)=3\sin x+4\cos x`.

Then `f(x)` at `x= -\frac{11\pi}{6}` is equal to :

JEE 2014 Mains Paper 1
A

`-\frac{3}{2} - 2 \sqrt{3}`

B

`frac{3}{2}-2\sqrt{3}`

C

`frac{3}{2}+2\sqrt{3}`

D

` -\frac{3}{2}+2\sqrt{3}`

Today's Score

0
Success Rate: NAN %

Practice & Test

Sr. No.SubjectTagCorrectRecorded Answer