Q .     A `20` cm long string, having a mass of `1.0` g, is fixed at both the ends. The tension in the string is `0.5 N`. The string is set into vibrations using an external vibrator of frequency `100 Hz`. Find the separation (in cm) between the successive nodes on the string.

JEE 2009
A

`0`

B

`1`

C

`5`

D

`4`

HINT

`v=sqrt(T/mu),
0
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