Q .     A particle is moving with velocity `vecv=K(yhati+xhatj),` where `K` is a constant. The general equation for its path is:

JEE 2010 Mains
A

`y=x^2`

B

`y^2=x+c`

C

`xy=c`

D

`y^2=x^2+c`

0
Success Rate: NAN %
Sr. No.SubjectTagCorrectRecorded Answer