Q .     A capacitor of capacity `0.1\ \muF` connected in series to a resistor of `10\M\Omega` is charged to a certain potential and then made to discharge through resistor. The time in which the potential will fall half of its original value is:
(Given, `log_{10}2=0.3010`)

BITSAT 2013
A

`2\ s`

B

`0.693\ s`

C

`0.5\ s`

D

`1.0\ s`

HINT

Charge on capacitor during discharging is given by , `q=q_0e^{-t/(RC)}`

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