Q .     The energy of a parallel plate capacitor when connected to a battery is `E`. With the battery still in connection, if the plates of the capacitor are separated so that the distance between them is twice the original distance, then electrostatic energy becomes:

EAMCET 2015
A

`2E`

B

`\ frac{E}{4}`

C

`\ frac{E}{2}`

D

`4E`

HINT

`E=\ frac{1}{2}CV^2 ` `\Rightarrow C\propto\ frac{1}{d}`

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