Q 1272556436.     In the given circuit, a battery of `10` V is connected across points `A` and `B` at time `t = 0`. If the capacitors have no charge initially, at what time (in second) does the voltage across them become `4` V? [Take: `ln 5 =1.6, ln 3 = 1.1`]

A

`7`

B

`2`

C

`5`

D

`4`

HINT

`q=q_0(1−e^(−t//t_c))`

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