Q 1928123901.     A mild wire of steel of length 1 m and cross sectional
area `0.5 xx 10^(-2) cm^2` is stretched, well
within its elastic limit, horizontally between two
pillars. A mass of 100 g is suspended from the
mid point of the wire. Calculate the depression
of the mid point . `g =10 m//S^2, Y = 2 xx 10^(11) N//m^2`

NCERT Chapter Solution 9/9.19

Solution for all Exercises of Physics Class 11 Chapter 9- MECHANICAL PROPERTIES OF SOLIDS

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Chapter 9 Solution

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