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If the circles `x^2 + y^2 + 2x + 2ky + 6 = 0` and `x^2 + y^2 + 2ky + k = 0` intersect orthogonally
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`(2^(3n)-1)` will be divisible by `(∀ n ϵ N)`
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For the variable , the locus of the point of intersection of the lines `3 tx - 2y + 6t = 0` and `3x
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GM and HM of two numbers are 10 and 8 respectively. The numbers are
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Best reagent for nuclear iodination of atomatic compounds is
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The line `y = x + lamda` is tangent to the ellipse `2x^2 + 3y^2 = 1`. Then, `lamda` is
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